(3x+3)(x+3)=3x^2-105

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Solution for (3x+3)(x+3)=3x^2-105 equation: 



(3x+3)(x+3)=3x^2-105

We move all terms to the left:

(3x+3)(x+3)-(3x^2-105)=0

We get rid of parentheses

-3x^2+(3x+3)(x+3)+105=0

We multiply parentheses ..

-3x^2+(+3x^2+9x+3x+9)+105=0

We get rid of parentheses

-3x^2+3x^2+9x+3x+9+105=0

We add all the numbers together, and all the variables

12x+114=0

We move all terms containing x to the left, all other terms to the right

12x=-114

x=-114/12

x=-9+1/2

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